## Chemistry and Chemical Reactivity (9th Edition)

a) $271\ mL$ b) No.
Mass of the soft drink, assuming it has water properties: $m=\rho V=0.997\ g/cm^3\times250.cm^3=249\ g$ Volume occupied by this mass when frozen: $V=m/\rho=249\ g \div 0.917\ g/cm^3 = 271\ cm^3=271\ mL$ Since this volume is bigger than the volume of the can, it cannot be contained by it.