#### Answer

a) $65\ m^3$, $65\times10^3\ L$
b) $65\ kg$, $140\ lb$
*The answer may be different depending on the value used for density of air. Be sure to use the density you are given to calculate.

#### Work Step by Step

a) The volume of the room is given by $V=L\times w\times h,\ L=18\ ft,\ w=15\ ft,\ h=8\ ft\ 6\ in=8.5\ ft$:
$V=2295\ ft^3$
In cubic meters:
$2295\ ft^3 \times \left(\frac{0.3048\ m}{1\ ft}\right)^3=65\ m^3$
In liters:
$65\ m^3 \times \frac{1000\ L}{1\ m^3}=65\times10^3\ L$
b) Density is given $\rho = 1\ g/L=1\times10^{-3}\ kg/L$, and, since we have the volume, the mass is:
$m=65\ kg$
In pounds:
$65\ kg \times \frac{1\ lb}{0.4539\ kg} = 140\ lb$