## Chemistry and Chemical Reactivity (9th Edition)

We use stoichiometry, making sure that all units cancel out to $kJ$, to obtain: $130\ Cal \times 4.18\ kJ/Cal = 543.4\ kJ$ We divide by the volume to find: $543.4\ kJ/335\ mL=1.62\ kJ/mL$ $630\ kJ/ 295\ mL = 2.14\ kJ/mL$