Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Let's Review: The Tools of Quantitative Chemistry - Study Questions - Page 43a: 14


$0.225\ cm^3$

Work Step by Step

We use stoichiometry, making sure that all units cancel out to $cm^3$, to obtain: $2.365\ g \div 10.5\ g/cm^3 = 0.225\ cm^3$
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