## Chemistry and Chemical Reactivity (9th Edition)

$250\ cm^3$ $0.250\ L$ $0.250\times10^{-3}\ m^3$ $0.250\ dm^3$
We use stoichiometry, making sure that all units cancel out to $cm^3, L, m^3, \text{and} \space dm^3$, respectively, to obtain: $250\ mL \times \begin{cases} 1\ cm^3/mL=250\ cm^3 \\ 1\ L/1000\ mL = 0.250\ L \\ 1\ m^3/10^6\ mL = 0.250\times10^{-3}\ m^3 \\ 1\ dm^3/1000\ mL = 0.250\ dm^3 \end{cases}$