## Chemistry and Chemical Reactivity (9th Edition)

data: work done by the system =$W =1.34KJ=1.34× 10^3J$ pressure= $P= 1.33 × 10^5 Pa$ to find: change in volume = Δ V =? in litre formula used: W = PΔ V by rearranging we get Δ V = W / P solution: Δ V = W / P $Δ V = (1.34 × 10^3J) / (1.33 × 10^5 Pa) as 1pa = 1 Kg/m.s^2$ so by converting into required units $Δ V = (1.34 × 10^3 Kgm^2/s^2) / (1.33 × 10^5Kg/m.s^2)$ $Δ V = 1.00 × 10^-2 m^3$ as $1m^3 = 1000l$ Δ V = 10 l so change in volume is 10 litre.