# Chapter 5 Principles of Chemical Reactivity: Energy and Chemical Reactions - Study Questions - Page 217a: 30

a. Work done by the system on the surrounding under given conditions is $-3.52 × 10^{3} J.$ b. Volume will decrease as total internal energy of system is decreased and heat is evolved from the system.

#### Work Step by Step

a) data: decrease in internal energy = ΔU = 1.65KJ energy transferred in the form of heat to the surroundings = q = -1.87KJ to find: work done by the system on the surrounding = -W = ? formula used: at constant pressure ΔU= q + W solution: according to sign conventions under given conditions ΔU = -q + (-W) W = -q - ΔU by putting the values in formula applied W = -1.87KJ - 1.65KJ W = - 3.52 KJ $as 1 KJ = 10^{3} J$ so $W = -3.52 × 10^{3} J$ so work done by the system on the surrounding under given conditions is $-3.52 × 10^{3} J.$ b) volume will decrease as total internal energy of system is decreased and heat is evolved from the system.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.