## Chemistry and Chemical Reactivity (9th Edition)

data: work done by the system =-W =-324J $pressure= P= 7.33 × 10^4 Pa$ to find: change in volume = Δ V =? formula used: W = -PΔ V by rearranging we get Δ V = - W / P solution: Δ V = - W / P $Δ V = (-324J) / (7.33 × 10^4 Pa)$ as $1pa = 1 Kg/m.s^2 1l = .001 m^3$ so by converting into required units $Δ V = (-324 Kgm^2/s^2) / (7.33 × 10^4Kg/m.s^2)$ $Δ V = - 4.42 × 10^{-3} m^3$ as $1m^3 = 1000l$ so by converting into required units Δ V = - 4.42 l so change in volume is 4.42 litre.