# Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179k: 129

$11.5\%$

#### Work Step by Step

Number of moles of AgCl: $0.1840\ g\div 143.33\ g/mol=1.284\ mmol$ From stoichiometry, number of moles of the compound: $0.642\ mmol$ Mass of the compound: $0.642\ mmol\times 221.03\ mg/mmol=141.9\ mg$ Mass percentage: $0.142/1.236\times 100\%=11.5\%$

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