## Chemistry and Chemical Reactivity (9th Edition)

Number of moles of HCl: $1.500\ M\times 24.26\ mL=36.39\ mmol$ Number of moles of the compound: $y=1.580\ g\div(158.35+x\times17.03)\ g/mol$ From stoichiometry: $0.0364/y=x$ $0.0364(158.35+x\times17.03)=1.580x$ $x=6.00$