Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179k: 127

Answer

6

Work Step by Step

Number of moles of HCl: $1.500\ M\times 24.26\ mL=36.39\ mmol$ Number of moles of the compound: $y=1.580\ g\div(158.35+x\times17.03)\ g/mol$ From stoichiometry: $0.0364/y=x$ $0.0364(158.35+x\times17.03)=1.580x$ $x=6.00$
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