Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179h: 98


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Work Step by Step

a) Number of moles of $SO_2$: $500.\ g\div 64.06\ g/mol= 7.805\ mol$ Number of moles of Zn: $125\ kg\div 65.38\ kg/kmol=1.91\ kmol$ $SO_2$ is the limiting reactant. From stoichiometry: $7.805\ mol\times 1\ mol\ ZnS_2O_4/2\ mol\ SO_2\times 1\ mol\ Na_2S_2O_4/1\ mol\ ZnS_2O_4\times 174.10\ g/mol=679.4\ g\ Na_2S_2O_4$ b) Mass percentage definition: $90.1/100*679.41=612\ g$
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