Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179h: 99


$66.5\ kg$

Work Step by Step

Number of moles of $CaCO_3$: $125.\ kg\times 95.0/100\div 100.09\ kg/kmol= 1.186\ kmol$ Mass of lime: $1.186\ kmol\times 56.08\ kg/kmol=66.5\ kg$
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