Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179h: 95



Work Step by Step

Number of moles of $O$: $(0.452-0.356)\ g\div 15.9994\ g/mol= 6.00\ mmol$, $3.00\ mmol$ of M Atomic weight of M: $0.356\ g\div 0.003\ mol= 118.7\ g/mol$, closest to Sn
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.