## Chemistry and Chemical Reactivity (9th Edition)

a) Sodium iodate, sodium bisulfite b) Number of moles of iodine: $1000\ g\div 253.81\ g/mol=3.94\ mol$ Mass of iodate: $3.94\ mol\times 2/1 \times 196.89\ g/mol=1551.5\ g$ Mass of bisulfite: $3.94\ mol\times 5/1 \times 104.06\ g/mol=2049.9\ g$ c) Number of moles of iodate: $15.0\ g\div 196.89\ g/mol=0.0762\ mol$ Number of moles of bisulfite: $0.125\ L\times 0.853\ M=0.107\ mol$ Ratio: $1.4\gt 5/2$, iodate is the limiting reactant. Mass of iodine: $0.0762\ mol\times 1/2\times 253.81\ g/mol=9.67\ g$