Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179g: 84

Answer

See answer below.

Work Step by Step

a) Number of moles of ammonia: $750.\ g\div 17.03\ g/mol=44.04\ mol$ Number of moles of oxygen: $750.\ g\div 32.00\ g/mol=23.44\ mol$, it's the limiting reactant. Mass of water: $23.44\ mol\times 6/5 \times 18.015\ g/mol=506.70\ g$ b) Mass of oxygen: $44.04\ mol\times 5/4 \times 32.00\ g/mol=1761.6\ g$
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