Answer
See answer below.
Work Step by Step
a) Titanium (IV) chloride, water, Titanium (IV) oxide, hydrochloric acid.
b) Number of moles of chloride:
$14.0\ mL\times 1.73\ g/mL\div 189.67\ g/mol=0.128\ mol$
Mass of water:
$0.128\ mol\times 2/1 \times 18.015\ g/mol=4.61\ g$
c) Mass of oxide:
$0.128\ mol\times 1/1 \times 79.87\ g/mol=10.22\ g$
Mass of acid:
$0.128\ mol\times 4/1 \times 36.46\ g/mol=18.67\ g$
