Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions: 109

Answer

a) Oxygen: $15.873\ u'$ Avogadro's Number $N'=5.9803\times10^{23}\ molecules/mol$ b) Hydrogen: $1.00798\ u'$ Avogadro's Number $N'=6.0278\times10^{23}\ molecules/mol$

Work Step by Step

a) For this standard $1.00794\ u = 1.0000\ u'$ Oxygen: $15.9994\ u \times 1.0000\ u'/1.00794\ u=15.873\ u'$ Carbon: $12.011\ u \times 1.0000\ u'/1.00794\ u=11.916\ u'$ Avogadro's Number $N'=(11.916/12.000)\times6.022\times10^{23}=5.9803\times10^{23}\ molecules/mol$ b) For this standard $15.9994\ u = 16.0000\ u'$ Hydrogen: $1.00794\ u \times 16.0000\ u'/15.9994\ u=1.00798\ u'$ Carbon: $12.011\ u \times 16.0000\ u'/15.9994\ u=12.011\ u'$ Avogadro's Number $N'=(12.011/12.000)\times6.022\times10^{23}=6.0278\times10^{23}\ molecules/mol$
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