## Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning

# Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95g: 117

#### Answer

$1.7\times10^{21}\ molecules$

#### Work Step by Step

Molar mass $18.015\ g/mol$ Mass of a drop: $0.050\ cm^3\times1.00\ g/cm^3=0.050\ g$ Number of moles in a drop: $0.050\ g/18.015\ g/mol = 2.8\times10^{-3}\ mol$ Number of molecules: $2.8\times10^{-3}\ mol\times6.022\times10^{23}\ molecules/mol=1.7\times10^{21}\ molecules$

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