Chemistry and Chemical Reactivity (9th Edition)

by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.

Published by Cengage Learning

ISBN 10: 1133949649

ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583d: 35

Answer

$K_c=37037.0$

Work Step by Step

$[CCl_4]=0.09\ mol/10.0\ L=0.009\ M = [S_2Cl_2]$ by stoichiometry $[CS_2]=0.12\ mol/10.0\ L-0.009\ M=0.003\ M$ $[Cl_2]=0.36\ mol/10.0\ L-3\times0.009\ M=0.009\ M$ $K_c=[S_2Cl_2][CCl_4]/[CS_2][Cl_2]^3$ $K_c=37037.0$

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