Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583d: 31

Answer

$K_c=3.883\times10^{-5}$

Work Step by Step

$[Br_2]_0=0.086\ mol\div 1.26\ L=0.068\ M$ $[Br_2]=0.068\ M(1-3.7/100)=0.657\ M$ $[Br]=2([Br_2]_0-[Br_2])=0.00505\ M$ $K_c=[Br]^2/[Br_2]=3.883\times10^{-5}$
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