# Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583d: 32

#### Work Step by Step

a) $K_2=[NO]/[N_2]^{1/2}[O_2]^{1/2}=K_1^{1/2}$ $K_2=0.041$ b) inverse reaction $K_2=1/K_1$ $K_2=588.2$

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