Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553c: 30


$4.33\ mg$

Work Step by Step

For a first-order process: $ln(C/C_0)=-kt;\ k=0.693/t_{1/2}$ For constant volume, we can use the equation on a mass basis. $ln (m/5.6\ mg)=-0.693/2.7\ d\times 1.0 \ d=4.33\ mg$
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