Answer
$4.33\ mg$
Work Step by Step
For a first-order process:
$ln(C/C_0)=-kt;\ k=0.693/t_{1/2}$
For constant volume, we can use the equation on a mass basis.
$ln (m/5.6\ mg)=-0.693/2.7\ d\times 1.0 \ d=4.33\ mg$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553c: 30
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