## Chemistry and Chemical Reactivity (9th Edition)

$r=0.04\ L/mol.s\cdot [C_2F_4]^2.$
For a second-order reaction, $1/[R]=kt+1/[R]_0$, and since this graph is a straight line for $[C_2F_4]$, this is a second-order reaction, and the rate constant is $+0.04\ L/mol.s$ The rate law is then: $r=0.04\ L/mol.s\cdot [C_2F_4]^2.$