Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553c: 38


$E_a=84.9\ kJ/mol$

Work Step by Step

From the Arrhenius equation: $ln(k_2/k_1)=-E_a/R(1/T_2-1/T_1)$ $ln(3)=-E_a/8.314\ J/mol.K(1/310\ K-1/300\ K)$ $E_a=84.9\ kJ/mol$
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