Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - 14-6 Reaction Mechanisms - Applying Chemical Principles - Questions - Page 550: 2


See the answer below.

Work Step by Step

The rate of the slow step is the determining rate: $r=r_S=k_S[H_2][I]^2$ For the fast equilibrium: $r_{-F}=k_{-F}[I]^2=r_F=k_{F}[I_2]\rightarrow [I]^2=k_F/k{-F}[I_2]=K_F[I_2]$ Overall rate: $r=(k_SK_F)[I_2][H_2]$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.