Answer
$Ea=185.73\ kJ/mol$
Work Step by Step
From the linear regression of ln k vs 1/T(in K):
$ln\ k=-22339/T(K)+26.186$
$-Ea/R=-22339\ K$
$Ea=185.73\ kJ/mol$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - 14-6 Reaction Mechanisms - Applying Chemical Principles - Questions - Page 550: 4
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