Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - 14-6 Reaction Mechanisms - Applying Chemical Principles - Questions - Page 550: 1


See the answer below.

Work Step by Step

a) $E=h\nu=hc/\lambda=6.626\times10^{-34}J.s\times 2.998\times10^{8}\ m/s\div578\times10^{-9}\ m$ $E=3.437\times10^{-19}\ J\rightarrow3.437\times10^{-19}\ J\times6.022\times10^{23}\ 1/mol$ $E=207.0\ kJ/mol$ b) $E=hcN/\nu\rightarrow 151000\ J/mol=6.626\times10^{-34}J.s\times 2.998\times10^{8}\ m/s\times6.022\times10^{23}\ 1/mol\div \nu$ $\nu = 792.2\ nm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.