Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505e: 87


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Work Step by Step

Freezing: $\Delta T_f=K_fm_f\rightarrow m_f=(3.1-5.50)^{\circ}C\div-5.12^{\circ}C/m=0.469\ m$ Boiling: $\Delta T_b=K_bm_b\rightarrow m_b=(82.6-80.10)^{\circ}C\div2.53^{\circ}C/m=0.988\ m$ Since the ratio of the two is approximately two, it's likely that at lower temperatures the prevalent form of benzoic acid is in dimers, caused by the hydrogen bonding (similar to what happens with acetic acid).
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