Answer
See the answer below.
Work Step by Step
Initial concentration:
$S=k_HP=0.034\ mol/kg.bar\times 1.5\ bar=0.051\ mol/kg$
New saturation concentration:
$S=k_HP^0=0.034\ mol/kg\times1.013\ bar = 0.034\ mol/kg$
The CO2 released is the difference between the saturation concentration:
$0.051-0.034=0.017\ mol/kg$ of beverage
