Chemistry and Chemical Reactivity (9th Edition)

A: $r=l/2$ Square area: $l^2=4r^2$ Area of the quarter circles: $4\times (\pi.r^2)/4=\pi.r^2$ Coverage: $\pi/4\times100\%=78.53\%$ B: $r=l/2$ Equilateral triangle area: $\sqrt3/4.l^2=\sqrt3.r^2$ Area of the 1/6th circles: $3\times (\pi.r^2)/6=\pi/2.r^2$ Coverage: $\pi/2\sqrt3\times100\%=90.69\%$