Chemistry and Chemical Reactivity (9th Edition)

by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.

Published by Cengage Learning

ISBN 10: 1133949649

ISBN 13: 978-1-13394-964-0

Chapter 12 The Solid State - Study Questions - Page 467d: 44

Answer

$N_A=6.0223\times10^{23}$

Work Step by Step

Volume: $(286.65\times10^{−10} cm)^3=2.355\times10^{−23} cm^3$ Mass: $7.874\ g/cm^3×2.355\times10^{−23} cm^3=1.855\times10^{−22} g$ $1.855\times10^{−22}\ g=(2×55.845)\ g/mol\div N_A$ $N_A=6.0223\times10^{23}$

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