## Chemistry and Chemical Reactivity (9th Edition)

Performing a regression, we obtain: $ln\ P(mmHg)=-4637.8\ K/T(K)+18.173$ From the Clausius-Clapeyron equation, it follows: $\Delta H_v=-4637.8\ K×-0.008314\ kJ/mol.K=38.56\ kJ/mol.K$