Answer
See the answer below.
Work Step by Step
From Graham's Law:
$\sqrt{\dfrac{\bar{u_A^2}}{\bar{u_B^2}}}=\sqrt{\dfrac{M_B}{M_A}}$
$1/3=\sqrt{4.0026\ g/mol/x}$
$x=36.02\ g/mol$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 10 Gases and Their Properties - Study Questions - Page 403d: 49
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