Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403d: 44


See the answer below.

Work Step by Step

For carbon monoxide: $\sqrt{\bar{u^2}}=\sqrt{3RT/M}$ $\sqrt{\bar{u^2}}=\sqrt{3×8.314\ J/mol.K×298\ K/0.028\ kg/mol}$ $\sqrt{\bar{u^2}}=515.2\ m/s$ For argon, from Graham's Law: $\sqrt{\dfrac{\bar{u_A^2}}{\bar{u_B^2}}}=\sqrt{\dfrac{M_B}{M_A}}$ $x/515.2\ m/s=\sqrt{28.0\ g/mol/39.948\ g/mol}$ $x=431.5\ m/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.