Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 7 - Sections 7.1-7.6 - Exercises - Problems by Topic - Page 331: 52

Answer

$3.25\times10^{3}ms$

Work Step by Step

λ = $\frac{h}{mv}$ or v= $\frac{h}{mλ}$ h = $6.626\times10^{-34}Js$ m = $1.67\times10^{-27}kg$ λ = 122 pm = $122\times10^{-12}m$ (given) v = $\frac{6.626\times10^{-34}Js}{1.67\times10^{-27}kg\times122\times10^{-12}m}$ = $3.25\times10^{3}m/s$
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