Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 7 - Sections 7.1-7.6 - Exercises - Problems by Topic - Page 331: 51

Answer

5.39 nm

Work Step by Step

λ = $\frac{h}{mv}$ h = $6.626\times10^{-34}Js$ m = $9.109\times10^{-31}kg$ v = $1.35\times10^{5}ms^{-1}$ λ = $\frac{6.626\times10^{-34}Js}{9.109\times10^{-31}kg\times1.35\times10^{5}ms^{-1}}$ = $5.39\times10^{-9}m$ = 5.39 nm
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