Answer
$7 mol$ $TiCl_4$
Work Step by Step
Choose the limiting reactant to determine how much $TiCl_{4}$ is produced.
$7$ $mol$ $Ti(avaliable)$
$17 mol$ $Cl_2$$\times\frac{1 mol TiCL_4}{2 mol Cl_{2}}$ $=8.5$ $mol$ $Ti (needed)$
Ti is the limiting reagent.
$7 mol$ $Ti$$\times\frac{1 mol TiCL_4}{1molTi}$ $=7 mol$ $TiCl_4$ can be produced
