Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 187: 38d


Aluminum (Al) is the limiting reactant.

Work Step by Step

Determine the limiting reactant. Choose one of the reactants and determine how much we need compared to how much is available. We choose to compare Al. $7.4$ $mol$ $Al (avaliable)$ $6.5 mol$ $O_{2}$$\times\frac{4 mol Al}{3 mol O_{2}}$ $=8.7$ $mol$ $Al (needed)$
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