Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 4 - Sections 4.1-4.9 - Exercises - Problems by Topic - Page 187: 35c


$4.24g\ H_{2}SO_{4}$

Work Step by Step

Divide the mass of the base by its molar mass to find the moles of base to react. Multiply this by the mole ratio from the balanced chemical equation to get the moles of acid. Finally, multiply the moles of acid by the molar mass of the acid to get the mass of acid. $4.85g\ KOH\times\frac{1mol\ KOH}{56.1056g\ KOH}\times\frac{1mol\ H_{2}SO_{4}}{2mol\ KOH}\times\frac{98.0785g\ H_{2}SO_{4}}{1mol\ H_{2}SO_{4}}=4.24g\ H_{2}SO_{4}$
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