#### Answer

$4.24g\ H_{2}SO_{4}$

#### Work Step by Step

Divide the mass of the base by its molar mass to find the moles of base to react. Multiply this by the mole ratio from the balanced chemical equation to get the moles of acid. Finally, multiply the moles of acid by the molar mass of the acid to get the mass of acid.
$4.85g\ KOH\times\frac{1mol\ KOH}{56.1056g\ KOH}\times\frac{1mol\ H_{2}SO_{4}}{2mol\ KOH}\times\frac{98.0785g\ H_{2}SO_{4}}{1mol\ H_{2}SO_{4}}=4.24g\ H_{2}SO_{4}$