Answer
$3.32M$ $C_{2}H_{6}O_{2}$
Work Step by Step
If we assume there is one mole of $C_{2}H_{6}O_{2}$ in a volume of solution, then 20% of the volume has a mass of $62.07g$. This means the total volume of solution weighs $62.07\div0.2=310.4g$. Since the density of the solution is $1.03\frac{g}{mL}$ the volume of the solution is :
$310.4g\div1.03\frac{g}{mL}=301.4mL=0.3014L$
The molarity of the solution is then:
$\frac{1mol}{0.3014mL}=3.32M$
