Answer
$KHSO_{3}(aq)+ HNO_{3}(aq)\ -->\ H_{2}O(l)+ SO_{2}(g)+ KNO_{3}(aq)$
Work Step by Step
$HNO_{3}$ neutralizes the $KHSO_{3}$ to form water. $SO_{2}$ is released from the $KHSO_{3}$ as a gas. This leaves aqueous $KNO_{3}$ in the solution.
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