Answer
$2C_{5}H_{12}O(l)+ 15O_{2}(g)\ -->\ 10CO_{2}(g)+ 12H_{2}O(g)$
Work Step by Step
A combustion reaction occurs. Add a 2 to $C_{5}H_{12}O$ so there is an even number of $O$ on the reactants side. The add a 10 to $CO_{2}$ to balance $C$ and a 12 to $H_{2}O$ to balance $H$. Finally, add a 15 to $O_{2}$ to balance $O$.
