Answer
The product depends upon the amount of oxygen. Tetraphosphorus hexaoxide, $P_{4}O_{6}(s)$, forms when oxygen is limited, and tetraphosphorus decaoxide, $P_{4}O_{10}(s)$, forms when greater amounts of oxygen are available.
Work Step by Step
White phosphorus reacts directly with oxygen to form phosphorus oxides, as in the reaction shown here:
$P_{4}(s) + 5 O_{2}(g) \rightarrow P_{4}O_{10}(s)$
