Answer
$NO_{2}$ : Oxidation state of N = +4
$HNO_{3}$ : Oxidation state of N = +5
$NO$ : Oxidation state of N = +2
Oxidizing agent : $HNO_{3}$ and $NO_{2}$
Reducing agent : $NO_{2}$
Work Step by Step
$NO_{2}$ : Oxidation state of N = +4
$HNO_{3}$ : Oxidation state of N = +5
$NO$ : Oxidation state of N = +2
$NO_{2}$is an oxidizing agent because it is reduced to $NO$ by gaining two electrons.
$NO_{2}$ is the reducing agent because it is oxidized to $HNO_{3}$ by losing 1 electron.
