Answer
$NO_{3}^{-}, NO_{2}^{-}, N_{3}^{-}, N_{2}H_{5}^{+}, NH_{4}^{+}$
Work Step by Step
$NO_{3}^{-}$ : Oxidation state of N = +5
$NO_{2}^{-}$ : Oxidation state of N = +3
$N{3}^{-}$ : Oxidation state of N = -1/3
$N_{2}H_{5}^{+}$ : Oxidation state of N = -2
$NH_{4}^{+}$ : Oxidation state of N = -3
