Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 22 - Sections 22.1-22.9 - Exercises - Problems by Topic - Page 1069: 29

Answer

See work below for details.

Work Step by Step

$NCl_{3}$ has a lone pair of electrons that $BCl_{3}$ lacks, giving it a trigonal pyramidal shape, with a bond angle of $\approx90^{\circ}$, as opposed to $BCl_{3}$ ’s trigonal planar shape with a bond angle of $\approx120^{\circ}$.
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