## Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall

# Chapter 20 - Sections 20.1-20.14 - Exercises - Problems by Topic - Page 993: 51

#### Answer

There are 3 structural isomers of $n-hexene$ formed by moving the position of the double bond. They are: 1. $CH_2=CH-CH_2-CH_2-CH_2-CH_3$ 2. $CH_3-CH=CH-CH_2-CH_2-CH_3$ 3. $CH_3-CH_2-CH=CH-CH_2-CH_3$

#### Work Step by Step

Since the hexyne molecule is linearly symmetrical, and the carbon chain is numbered to give the lowest number to the double bond, there can be 3 structural isomers of n-hexene formed by moving the position of the double bond. They are - 1. $CH_2=CH-CH_2-CH_2-CH_2-CH_3 \ ( 1-hexene)$ 2. $CH_3-CH=CH-CH_2-CH_2-CH_3 \ ( 2-hexene)$ 3. $CH_3-CH_2-CH=CH-CH_2-CH_3 \ ( 3-hexene)$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.