Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 92


$8.06\times10^{28}\ atoms\ He $

Work Step by Step

1. Use the molar mass of helium and Avogadro's number as conversion factors in order to determine the number of helium atoms. 2. $536\times10^{3} g\ He \times\frac{1\ mol\ He}{4\ g\ He}\times\frac{6.022\times10^{23}}{1\ mol\ He}= 8.06\times10^{28}\ atoms\ He $
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