Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic - Page 82: 90b

$ 794\ kg\ Ni $

1. Use Avogadro's number to convert from atoms to moles of nickel. Then use the molar mass of nickel to convert from moles to grams of nickel. Finally, convert grams into kilograms. 2. $8.15\times10^{27}\ atoms\ Ni\times\frac{1\ mol\ Ni}{6.022\times 10^{23}\ atoms\ Ni}\times\frac{58.7\ g \ Ni}{1\ mol\ Ni}\times\frac{1\ kg\ Ni}{1000\ g\ Ni}= 794\ kg\ Ni $