Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Problems by Topic: 88d


$4.949\times10^{23}\ atoms\ Sn $

Work Step by Step

1. Use the molar mass of tin and Avogadro's number as conversion factors in order to determine the number of atoms of tin. 2. $97.522 g\ Sn \times\frac{1\ mol\ Sn}{118.71\ g\ Sn}\times\frac{6.022\times10^{23}}{1\ mol\ Sn}= 4.949\times10^{23}\ atoms\ Sn $
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